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āĻļā§‚āĻ¨ā§āϝ āϭ⧇āĻ•ā§āϟāϰ āĻāϰ āϤāĻžā§ŽāĻĒāĻ°ā§āϝ āϞ⧇āĻ–

āĻāĻ•āϟāĻŋ āĻ•āύāĻž āϕ⧋āύ āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻĨ⧇āϕ⧇ āϝāĻžāĻ¤ā§āϰāĻž āĻļ⧁āϰ⧁ āĻ•āϰ⧇ āĻ•āĻŋāϛ⧁ āϏāĻŽāϝāĻŧ āĻĒāϰ⧇ āφāĻŦāĻžāϰ āĻ“āχ āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āĻĢāĻŋāϰ⧇ āĻāϞ⧇ āĻ•āĻŖāĻžāϟāĻŋāϰ āϏāϰāĻŖ āĻļā§‚āĻ¨ā§āϝ āĻšāϝāĻŧ āĨ¤ āϝ⧇āĻšā§‡āϤ⧁ āĻāϟāĻŋ āĻāĻ•āϟāĻŋ āϭ⧇āĻ•ā§āϟāϰ āϰāĻžāĻļāĻŋ āϤāĻžāχ āĻāχ āĻļā§‚āĻ¨ā§āϝāϟāĻŋ āĻšāĻŦ⧇ āĻāĻ•āϟāĻŋ āϭ⧇āĻ•ā§āϟāϰ āĨ¤  āφāĻŦāĻžāϰ āϕ⧋āύ āĻŦāĻ¸ā§āϤ⧁āϰ āĻ“āĻĒāϰ āĻŦāϞ āĻŦāĻŋāϝāĻŧāĻž āĻ•āϰāϞ⧇ āĻŦāĻ¸ā§āϤ⧁āϰ āϏāĻžāĻŽā§āϝāĻŦāĻ¸ā§āĻĨāĻžāϝāĻŧ āĻĨāĻžāϕ⧇ āĻ…āĻ°ā§āĻĨāĻžā§Ž āĻŦāĻ¸ā§āϤ⧁āϰ āωāĻĒāϰ āĻ•ā§āϰāĻŋāϝāĻŧāĻžāĻļā§€āϞ āϞāĻŦā§āϧāĻŋ āĻŦāϞ āĻļā§‚āĻ¨ā§āϝ āĻšāϝāĻŧāĨ¤ āϞāĻŦā§āϧāĻŋ āĻŦāϞ āĻļā§‚āĻ¨ā§āϝ āĻāχ āωāĻ•ā§āϤāĻŋāϟāĻŋ āĻĨ⧇āϕ⧇ āĻŦā§‹āĻāĻž āϝāĻžāϝāĻŧ āĻāχ āĻļā§‚āĻ¨ā§āϝ āϟāĻŋ āĻ¸ā§āϕ⧇āϞāĻžāϰ āύāϝāĻŧ āĻŦāϰāĻ‚ āĻāĻ•āϟāĻŋ āϭ⧇āĻ•ā§āϟāϰ⧇āϰ āĨ¤ āĻāχ āϭ⧇āĻ•ā§āϟāϰ āϕ⧇āχ āĻļā§‚āĻ¨ā§āϝ āϭ⧇āĻ•ā§āϟāϰ āĻŦāϞāĻž āĻšāϝāĻŧ  āĻ…āĻ°ā§āĻĨāĻžā§Ž āĻĻ⧁āϟāĻŋ āϏāĻŽāĻŽāĻžāύāϰ āϭ⧇āĻ•ā§āϟāϰ⧇āϰ āĻŦāĻŋāϝāĻŧā§‹āĻ— āĻĢāϞ āĻšāϞ āĻļā§‚āĻ¨ā§āϝ āϭ⧇āĻ•ā§āϟāϰ āφāĻŦāĻžāϰ āϏāĻŽāĻŦ⧇āϗ⧇ āĻ—āϤāĻŋāĻļā§€āϞ āĻāĻ•āϟāĻŋ āĻ•āĻŖāĻžāϰ āĻ¤ā§āĻŦāϰāĻŖ āĻļā§‚āĻ¨ā§āϝ āĨ¤ āĻāϟāĻŋāĻ“  āĻāĻ•āϟāĻŋ āϭ⧇āĻ•ā§āϟāϰ āϰāĻžāĻļāĻŋ āĻ•āĻžāϰāĻŖ āĻ¤ā§āĻŦāϰāĻŖ āĻāĻ•āϟāĻŋ āϭ⧇āĻ•ā§āϟāϰ āϰāĻžāĻļāĻŋāĨ¤ āϏ⧁āϤāϰāĻžāĻ‚ āĻĻ⧇āĻ–āĻž āϝāĻžāĻšā§āϛ⧇ āϭ⧇āĻ•ā§āϟāϰ āĻŦā§€āϜāĻ—āĻŖāĻŋāϤ⧇āϰ āĻļā§‚āĻ¨ā§āϝ āϭ⧇āĻ•ā§āϟāϰ⧇āϰ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ…āĻĒāϰāĻŋāĻšāĻžāĻ°ā§āϝāĨ¤

āϤāϰāϞ⧇āϰ āĻĒā§āϰāϏāĻžāϰāĻŖ āĻšāĻžāϰ āϕ⧀ āϏāĻŦ āωāĻˇā§āĻŖāϤāĻžāϝāĻŧ āϏāĻŽāĻžāύ āĻĨāĻžāϕ⧇?

āύāĻž āϤāϰāϞ⧇āϰ āĻĒā§āϰāϏāĻžāϰāĻŖ āĻšāĻžāϰ āϏāĻŦ‌ āωāĻˇā§āĻŖāϤāĻžāϝāĻŧ  āϏāĻŽāĻžāύ āĻĨāĻžāϕ⧇ āύāĻžāĨ¤  āωāĻˇā§āĻŖāϤāĻžāϰ āĻŦāĻŋāĻ­āĻŋāĻ¨ā§āύ āĻĒāĻžāĻ˛ā§āϞāĻžāϝāĻŧ āϤāϰāϞ⧇āϰ āĻĒā§āϰāϏāĻžāϰāĻŖ āĻāϰ āĻšāĻžāϰ āϏāĻžāĻŽāĻžāĻ¨ā§āϝ āĻĒāϰāĻŋāĻŦāĻ°ā§āϤāĻŋāϤ āĻšāϝāĻŧāĨ¤

uniqueness of centre of gravity

An object cannot have two centre of gravity  . This is called  the uniqueness of  centre of gravity. Let us suppose an object has two centre gravity G and G' now as per the definition of centre of gravity at  any posture of the object the gravity force will act  through the point G and G' . On the other hand gravity always acts vertically downwards .so GG' will be always vertical line.  For any posture of the object GG' should be vertical that cannot be possible .  so an object cannot have two centre of gravity . It is an unique point for an object.

wbchse previous year question paper class 11 math (2014) | West Bengal Board |

āϏāĻŽā§āĻ­āĻŦāύāĻž āϤāĻ¤ā§āĻŦ ( probability ) āĻāϰ āϜāĻ¨ā§āϝ āĻŦāĻŋāĻ­āĻŋāĻ¨ā§āύ āϤāĻžāϏ⧇āϰ āĻŦāĻžāĻ‚āϞāĻž āύāĻžāĻŽ āĻ“ āϏāĻ‚āĻ–ā§āϝāĻž

cards(āϤāĻžāϏ) Ruhiton(diamonds),Haroton(hearts),Ishkapon (spades), Chireton(Clubs) ace = āĻŸā§‡āĻ•ā§āĻ•āĻž jack = āĻ—ā§‹āϞāĻžāĻŽ Face card = king or queen or jack

āĻĨāĻžāĻ°ā§āĻŽā§‹āĻŽāĻŋāϟāĻžāϰ⧇āϰ āĻŦāĻžāĻ˛ā§āĻŦ⧇āϰ āφāϝāĻŧāϤāύ 1`cm^3`āĨ¤ āϏ⧇āχ āĻĨāĻžāĻ°ā§āĻŽā§‹āĻŽāĻŋāϟāĻžāϰ⧇āϰ āĻĒā§āϰāϤāĻŋāϟāĻŋ āĻĄāĻŋāĻ—ā§āϰāĻŋ āĻŦāĻŋāĻ­āĻžāĻ— 5 āĻŽāĻŋāĻŽāĻŋ āĻĻā§€āĻ°ā§āϘ āĻšāĻ“āϝāĻŧāĻž āωāϚāĻŋāϤāĨ¤ āĻĨāĻžāĻ°ā§āĻŽā§‹āĻŽāĻŋāϟāĻžāϰ āϟāĻŋāωāĻŦ⧇āϰ āĻ•ā§āϰāϏ-āĻŦāĻŋāĻ­āĻžāĻ—ā§€āϝāĻŧ āĻ…āĻžā§āϚāϞāϟāĻŋ āϕ⧀ āĻšāĻŦ⧇? āĻ—ā§āϞāĻžāϏ⧇āϰ āϏāĻžāĻĨ⧇ āϏāĻŽā§āĻŽāĻžāύ⧇āϰ āϏāĻžāĻĨ⧇ āĻĒāĻžāϰāĻĻāϟāĻŋāϰ āφāĻĒāĻžāϤ āĻŦāĻŋāĻ¸ā§āϤāĻžāϰ⧇āϰ āϗ⧁āĻŖāĻŽāĻžāύ`1.6 times 10^(-4@)C^(-1)`āĨ¤

Please comment below if you want detail explanation 

Balance the following reaction with oxidation number method: Cu + HNO3 = Cu(NO3)2 + NO + H2O

āĻŦāĻŋāĻ­āĻŋāĻ¨ā§āύ āĻĒā§āϰāĻ•āĻžāϰ āύāĻžāϞāĻŋāĻ•āĻž āĻŦāĻžāĻ¨ā§āĻĄāĻŋāϞ ( Vascular bundle )

what will happen if Mean deviation or average deviation does not contain modulus sign

āϕ⧋āύ⧋ āϏāĻŽāĻžāĻ¨ā§āϤāϰ āĻļā§āϰ⧇āĻŖā§€āϰ p āϤāĻŽ āĻĒāĻĻ a , q āϤāĻŽ āĻĒāĻĻ b āĻšāϞ⧇ āĻĒā§āϰāĻŽāĻžāĻŖ āĻ•āϰ ( p + q ) āϏāĻ‚āĻ–ā§āϝāĻ• āĻĒāĻĻ⧇āϰ āϏāĻŽāĻˇā§āϟāĻŋ (p+q)/2(a+b+(a-b)/(p-q))

5 f(x) + 3 f(1/x) = x + 2 and y = x f(x) then find dy/dx at x = 1

m āϏāĻ‚āĻ–ā§āϝāĻ• āĻĒāĻĻ GP āϤ⧇ āφāϛ⧇ āϝāĻžāĻĻ⧇āϰ āϏāĻžāϧāĻžāϰāĻŖ āĻ…āύ⧁āĻĒāĻžāϤ āĻšāϞ r āĻāĻŦāĻ‚ āϝ⧋āĻ— āĻĢāϞ `S_(m)` āĻšāϞ⧇ āĻĻ⧇āĻ–āĻžāĻ“ āϝ⧇ āĻĻ⧁āϟāĻŋ āĻ•āϰ⧇ āĻĒāĻĻ āĻāĻ•āĻ¤ā§āϰ⧇ āϗ⧁āύ āĻ•āϰ⧇ āϝ⧋āĻ— āĻ•āϰāϞ⧇ āϝ⧋āĻ—āĻĢāϞ =( r/(r+1))*`S_(m)``*S_(m - 1)`

āĻŦāĻŋāĻ­āĻŋāĻ¨ā§āύ āĻĒā§āϰāĻ•āĻžāϰ⧇āϰ āĻ—ā§āϰāĻžāĻšāĻ• ( receptor)

Ionisatio Enthalpy and Electron gain Enthalpy

differentiability continuity and existence of a limit

a=1/sqrt(2)(1+i) āĻšāϞ⧇ āĻĻ⧇āĻ–āĻžāĻ“ āϝ⧇ a^6+a^4+a^2+1=0

show that (cot(θ)-tan(θ))/(1-2sin^2(θ))=sec(θ)cosec(θ)

prove that tan(70°)=2tan(40°)+tan(20°)+4tan(10°)

āĻ¸ā§āϟāĻŋāϞāĻŋ

āĻŦāĻŋāĻ­āĻŋāĻ¨ā§āύ āĻĢāϞ āĻ“ āϤāĻžāϰ āĻ­ā§‹āĻœā§āϝ āĻ…āĻ‚āĻļ āĻāĻŦāĻ‚ āĻĒā§āϰāĻ•ā§ƒāϤāĻŋ