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āĻļূāύ্āϝ āĻ­েāĻ•্āϟāϰ āĻāϰ āϤাā§ŽāĻĒāϰ্āϝ āϞেāĻ–

āĻāĻ•āϟি āĻ•āύা āĻ•োāύ āĻŦিāύ্āĻĻু āĻĨেāĻ•ে āϝাāϤ্āϰা āĻļুāϰু āĻ•āϰে āĻ•িāĻ›ু āϏāĻŽāϝ় āĻĒāϰে āφāĻŦাāϰ āĻ“āχ āĻŦিāύ্āĻĻুāϤে āĻĢিāϰে āĻāϞে āĻ•āĻŖাāϟিāϰ āϏāϰāĻŖ āĻļূāύ্āϝ āĻšāϝ় । āϝেāĻšেāϤু āĻāϟি āĻāĻ•āϟি āĻ­েāĻ•্āϟāϰ āϰাāĻļি āϤাāχ āĻāχ āĻļূāύ্āϝāϟি āĻšāĻŦে āĻāĻ•āϟি āĻ­েāĻ•্āϟāϰ ।  āφāĻŦাāϰ āĻ•োāύ āĻŦāϏ্āϤুāϰ āĻ“āĻĒāϰ āĻŦāϞ āĻŦিāϝ়া āĻ•āϰāϞে āĻŦāϏ্āϤুāϰ āϏাāĻŽ্āϝāĻŦāϏ্āĻĨাāϝ় āĻĨাāĻ•ে āĻ…āϰ্āĻĨাā§Ž āĻŦāϏ্āϤুāϰ āωāĻĒāϰ āĻ•্āϰিāϝ়াāĻļীāϞ āϞāĻŦ্āϧি āĻŦāϞ āĻļূāύ্āϝ āĻšāϝ়। āϞāĻŦ্āϧি āĻŦāϞ āĻļূāύ্āϝ āĻāχ āωāĻ•্āϤিāϟি āĻĨেāĻ•ে āĻŦোāĻা āϝাāϝ় āĻāχ āĻļূāύ্āϝ āϟি āϏ্āĻ•েāϞাāϰ āύāϝ় āĻŦāϰং āĻāĻ•āϟি āĻ­েāĻ•্āϟāϰেāϰ । āĻāχ āĻ­েāĻ•্āϟāϰ āĻ•েāχ āĻļূāύ্āϝ āĻ­েāĻ•্āϟāϰ āĻŦāϞা āĻšāϝ়  āĻ…āϰ্āĻĨাā§Ž āĻĻুāϟি āϏāĻŽāĻŽাāύāϰ āĻ­েāĻ•্āϟāϰেāϰ āĻŦিāϝ়োāĻ— āĻĢāϞ āĻšāϞ āĻļূāύ্āϝ āĻ­েāĻ•্āϟāϰ āφāĻŦাāϰ āϏāĻŽāĻŦেāĻ—ে āĻ—āϤিāĻļীāϞ āĻāĻ•āϟি āĻ•āĻŖাāϰ āϤ্āĻŦāϰāĻŖ āĻļূāύ্āϝ । āĻāϟিāĻ“  āĻāĻ•āϟি āĻ­েāĻ•্āϟāϰ āϰাāĻļি āĻ•াāϰāĻŖ āϤ্āĻŦāϰāĻŖ āĻāĻ•āϟি āĻ­েāĻ•্āϟāϰ āϰাāĻļি। āϏুāϤāϰাং āĻĻেāĻ–া āϝাāϚ্āĻ›ে āĻ­েāĻ•্āϟāϰ āĻŦীāϜāĻ—āĻŖিāϤেāϰ āĻļূāύ্āϝ āĻ­েāĻ•্āϟāϰেāϰ āĻŦ্āϝāĻŦāĻšাāϰ āĻ…āĻĒāϰিāĻšাāϰ্āϝ।

āϤāϰāϞেāϰ āĻĒ্āϰāϏাāϰāĻŖ āĻšাāϰ āĻ•ী āϏāĻŦ āωāώ্āĻŖāϤাāϝ় āϏāĻŽাāύ āĻĨাāĻ•ে?

āύা āϤāϰāϞেāϰ āĻĒ্āϰāϏাāϰāĻŖ āĻšাāϰ āϏāĻŦ‌ āωāώ্āĻŖāϤাāϝ়  āϏāĻŽাāύ āĻĨাāĻ•ে āύা।  āωāώ্āĻŖāϤাāϰ āĻŦিāĻ­িāύ্āύ āĻĒাāϞ্āϞাāϝ় āϤāϰāϞেāϰ āĻĒ্āϰāϏাāϰāĻŖ āĻāϰ āĻšাāϰ āϏাāĻŽাāύ্āϝ āĻĒāϰিāĻŦāϰ্āϤিāϤ āĻšāϝ়।

uniqueness of centre of gravity

An object cannot have two centre of gravity  . This is called  the uniqueness of  centre of gravity. Let us suppose an object has two centre gravity G and G' now as per the definition of centre of gravity at  any posture of the object the gravity force will act  through the point G and G' . On the other hand gravity always acts vertically downwards .so GG' will be always vertical line.  For any posture of the object GG' should be vertical that cannot be possible .  so an object cannot have two centre of gravity . It is an unique point for an object.

wbchse previous year question paper class 11 math (2014) | West Bengal Board |

āϏāĻŽ্āĻ­āĻŦāύা āϤāϤ্āĻŦ ( probability ) āĻāϰ āϜāύ্āϝ āĻŦিāĻ­িāύ্āύ āϤাāϏেāϰ āĻŦাংāϞা āύাāĻŽ āĻ“ āϏংāĻ–্āϝা

cards(āϤাāϏ) Ruhiton(diamonds),Haroton(hearts),Ishkapon (spades), Chireton(Clubs) ace = āϟেāĻ•্āĻ•া jack = āĻ—োāϞাāĻŽ Face card = king or queen or jack

āĻĨাāϰ্āĻŽোāĻŽিāϟাāϰেāϰ āĻŦাāϞ্āĻŦেāϰ āφāϝ়āϤāύ 1`cm^3`। āϏেāχ āĻĨাāϰ্āĻŽোāĻŽিāϟাāϰেāϰ āĻĒ্āϰāϤিāϟি āĻĄিāĻ—্āϰি āĻŦিāĻ­াāĻ— 5 āĻŽিāĻŽি āĻĻীāϰ্āϘ āĻšāĻ“āϝ়া āωāϚিāϤ। āĻĨাāϰ্āĻŽোāĻŽিāϟাāϰ āϟিāωāĻŦেāϰ āĻ•্āϰāϏ-āĻŦিāĻ­াāĻ—ীāϝ় āĻ…āĻž্āϚāϞāϟি āĻ•ী āĻšāĻŦে? āĻ—্āϞাāϏেāϰ āϏাāĻĨে āϏāĻŽ্āĻŽাāύেāϰ āϏাāĻĨে āĻĒাāϰāĻĻāϟিāϰ āφāĻĒাāϤ āĻŦিāϏ্āϤাāϰেāϰ āĻ—ুāĻŖāĻŽাāύ`1.6 times 10^(-4@)C^(-1)`।

Please comment below if you want detail explanation 

Balance the following reaction with oxidation number method: Cu + HNO3 = Cu(NO3)2 + NO + H2O

āĻŦিāĻ­িāύ্āύ āĻĒ্āϰāĻ•াāϰ āύাāϞিāĻ•া āĻŦাāύ্āĻĄিāϞ ( Vascular bundle )

what will happen if Mean deviation or average deviation does not contain modulus sign

āĻ•োāύো āϏāĻŽাāύ্āϤāϰ āĻļ্āϰেāĻŖীāϰ p āϤāĻŽ āĻĒāĻĻ a , q āϤāĻŽ āĻĒāĻĻ b āĻšāϞে āĻĒ্āϰāĻŽাāĻŖ āĻ•āϰ ( p + q ) āϏংāĻ–্āϝāĻ• āĻĒāĻĻেāϰ āϏāĻŽāώ্āϟি (p+q)/2(a+b+(a-b)/(p-q))

5 f(x) + 3 f(1/x) = x + 2 and y = x f(x) then find dy/dx at x = 1

m āϏংāĻ–্āϝāĻ• āĻĒāĻĻ GP āϤে āφāĻ›ে āϝাāĻĻেāϰ āϏাāϧাāϰāĻŖ āĻ…āύুāĻĒাāϤ āĻšāϞ r āĻāĻŦং āϝোāĻ— āĻĢāϞ `S_(m)` āĻšāϞে āĻĻেāĻ–াāĻ“ āϝে āĻĻুāϟি āĻ•āϰে āĻĒāĻĻ āĻāĻ•āϤ্āϰে āĻ—ুāύ āĻ•āϰে āϝোāĻ— āĻ•āϰāϞে āϝোāĻ—āĻĢāϞ =( r/(r+1))*`S_(m)``*S_(m - 1)`

āĻŦিāĻ­িāύ্āύ āĻĒ্āϰāĻ•াāϰেāϰ āĻ—্āϰাāĻšāĻ• ( receptor)

Ionisatio Enthalpy and Electron gain Enthalpy

differentiability continuity and existence of a limit

a=1/sqrt(2)(1+i) āĻšāϞে āĻĻেāĻ–াāĻ“ āϝে a^6+a^4+a^2+1=0

show that (cot(θ)-tan(θ))/(1-2sin^2(θ))=sec(θ)cosec(θ)

prove that tan(70°)=2tan(40°)+tan(20°)+4tan(10°)

āϏ্āϟিāϞি

āĻŦিāĻ­িāύ্āύ āĻĢāϞ āĻ“ āϤাāϰ āĻ­োāϜ্āϝ āĻ…ংāĻļ āĻāĻŦং āĻĒ্āϰāĻ•ৃāϤি